4x^2-4=54

Solution for 4x^2-4=54 equation:

4x^2-4=54

We move all terms to the left:

4x^2-4-(54)=0

We add all the numbers together, and all the variables

4x^2-58=0

a = 4; b = 0; c = -58;
Δ = b2-4ac
Δ = 02-4·4·(-58)
Δ = 928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{928}=\sqrt{16*58}=\sqrt{16}*\sqrt{58}=4\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{58}}{2*4}=\frac{0-4\sqrt{58}}{8}
=-\frac{4\sqrt{58}}{8}
=-\frac{\sqrt{58}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{58}}{2*4}=\frac{0+4\sqrt{58}}{8}
=\frac{4\sqrt{58}}{8}
=\frac{\sqrt{58}}{2}
$